Re: isometries, and symmetry groups
On 2008-03-31, Narcoleptic Insomniac <i_have_narcoleptic_insomnia@xxxxxxxxx> wrote:
Of course, that begs the question: Is Homeo(M) =~ Isom(M) for every
metric space M? Intuitively, I would like to say yes,
It is easy to construct counterexamples, one of the smallest being
{1,2,4} with the usual Euclidean metric. It has only the identity
isometry, but 6 homeomorphisms.
- Tim
.
Relevant Pages
- Re: 2-manifold metric spaces with many symmetries
... >> isometry that maps the first triangle to the second. ... > I'm not sure what you mean by a 2-D metric space. ... and if there is an r>0 such that the open ball of radius r ... David Bernier ...
(sci.math) - Re: -- The "most natural" completion of a metric space
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(sci.math) - 2-manifold metric spaces with many symmetries
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(sci.math) - Re: Complete bounded metric space
... all homeomorphisms from X onto itself. ... Prove that is a complete metric space. ... You can't be totally stuck. ... Write a few sentences indicating you at ...
(sci.math) - Complete bounded metric space
... Let be a complete bounded metric space and let G be the set of ... all homeomorphisms from X onto itself. ... Prove that is a complete metric space. ... I'm stuck. ...
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