Re: simple groups and permutation groups
- From: quasi <quasi@xxxxxxxx>
- Date: Tue, 01 Apr 2008 15:38:50 -0500
On 1 Apr 2008 19:18:25 GMT, Marc Olschok <nobody@xxxxxxxxxxxxxxx>
wrote:
quasi <quasi@xxxxxxxx> wrote:
On 31 Mar 2008 19:31:09 GMT, Marc Olschok <nobody@xxxxxxxxxxxxxxx>
wrote:
quasi <quasi@xxxxxxxx> wrote:
On Mon, 31 Mar 2008 00:39:44 EDT, Jack Schmidt
<Jack.Schmidt.SciMath@xxxxxxxxx> wrote:
Let G be a simple group and let f : S_n --> G be a
surjective homomorphism for some positive integer n.
Why is G isomorphic to S_k, for some k =< n ?
Because G is cyclic of order two and n>=2.
Which would make it a trick question.
If that was really the wording of the assigned question then, while
technically not incorrect, I suspect the problem was posed in error.
Looks o.k. to me. The question is
Any simple epimorphic image of a permutation group S_n is
already isomorphic to some S_k.
Except that the only such simple epimorphic images are either the
trivial group or Z_2. Hence, unless it was an intentional trick
question, it seems liklely that the proposer of the problem was
confused about the set of possible isomorphism types.
Sorry, I had misread the text all the time by automatically
substituting "A_n" for "S_n". Does the question look more reasonable now?
I'd have to see the actual question.
quasi
.
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