Re: 2^ aleph_x =/= aleph(x+1) !! aleph = beth !!
- From: amy666 <tommy1729@xxxxxxxxxxx>
- Date: Wed, 02 Apr 2008 09:55:01 EDT
LOL !!!
so you all actually insist that 2^aleph_x =/= aleph_(x+1) and i am " confused with the beth numbers.
but APPARENTLY you guys are unaware that :
from the axiom of choice and the generalized continuum hypothesis it follow that :
THE SEQUENCE OF BETH NUMBERS EQUALS THE SEQUENCE OF ALEPH NUMBERS !!!!
thus 2^beth_x = beth_(x+1) and THUS 2^aleph_x = aleph_(x+1)
aha !!
take that.
who is confused now !!!???
so its not me taking sugar every morning.
take your meds dennis, until you see AC and GCH imply aleph = beth => 2^aleph_x = aleph_(x+1)
tommy1729
.
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