Re: Finding minimum in arithmetic series modulo N
- From: James Waldby <no@xxxxx>
- Date: Thu, 10 Apr 2008 21:00:05 -0500
On Thu, 10 Apr 2008 15:33:03 -0700, 3130 wrote:
Consider the sequence of values generated by:[...]
x(k) = (A + kD) mod N
where A, D and N are positive non-zero integers, and k takes values 0,
1, 2 ... M-1.
Other then brute force search, is there is a way to determine the
minimum value for x(k) and the value of k for which that minimum value
occurs.
Here's an idea to consider; still a brute force search, but
with a good chance of terminating much earlier than when
just stepping k=1,2,3... -- Suppose gcd(D,N) = 1. From
Euclid's algorithm, let a,b be such that 1 = aD+bN, so that
aD == 1 mod N. Let i be the smallest integer such that
0 < -a + iN < N. (i exists since (D,N) = 1.)
Let c = -a+iN and k = Ac mod N. (Now A + kD == 0 mod N.)
Until k is in range, set k to k+a mod N.
Afterward, compute min = A+kD modulo N.
(I haven't figured out how to adapt this if gcd(D,N) > 1.)
-jiw
.
- Follow-Ups:
- Re: Finding minimum in arithmetic series modulo N
- From: Ilmari Karonen
- Re: Finding minimum in arithmetic series modulo N
- From: quasi
- Re: Finding minimum in arithmetic series modulo N
- Prev by Date: Re: Finding minimum in arithmetic series modulo N
- Next by Date: Re: math word problem
- Previous by thread: Re: Finding minimum in arithmetic series modulo N
- Next by thread: Re: Finding minimum in arithmetic series modulo N
- Index(es):