Paradox of simplification or one more flew ?
- From: "Roman B. Binder" <rbinder@xxxxxxxxxxxxxxxx>
- Date: Tue, 15 Apr 2008 15:43:54 EDT
Hi,
What could be really significant for FLT ?
See smart possibility for the proof from
following substitutions:
1): once X is odd and not divided by p :
X = m^2 - n^2
Y = 2mn + y
Z = m^2 + n^2 + z
2): once Y is even and not divided by p :
Y = 2mn
X = m^2 - n^2 + x
Z = m^2 + n^2 + z
where m>n and m;n natural values of gcd=1
and one of them is even number as in pythagorean
triplets selected in such way that:
in the case 1):
X = x1*x2 = b[b^(p-1) + p^u atr] *)
x1 = b = m-n ; x2 = m + n ;
where x1<<x2 ; m-n<<m+n ;
in the case 2):
Y = y1*y2 = a[a^(p-1) + p^u btr] *)
y1 = a = 2n ; y2 = m ;
where y1<<y2 ; 2n<<m ;
and where z;y or x are proper integers
for to achieve: X^p + Y^p = Z^p
Now in some approximately elementary
developments it used be to look for
some N^2 = 2m^2 +1 = (m+n)^2
and the first is: m=2;n=1; N=3
then: m=12; n=5; N=17
etc.etc.
Why ?
For to be familiar with P. Fermat,
when he neglected to write out his last
theorems proof.
*): previously prime exponent
used to be stated with n :
X^n + Y^n + Z^n ?
but as already we have some n
in classics pythagorean triplets
so lets take in the place n prime p>=3.
Then in some advanced developments I used to describe:
X = b[b^(n-1) + n^u atp] so it should be changed to:
X = b[b^(p-1) + p^u atr]
etc. etc.
On the other side, if P. Fermat had used to mention
such hint in his margin, there was not yet so much
improvements in mathematics:
Shortly he succeed to make us crazy:
any other passage is extremely harder !!!
Best regards
Ro-Bin
.
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