Re: Local Homeomorphisms



On 16.04.2008 10:18, William Elliot wrote:
Let f:X -> Y be a local homeomorphism.

If X is connected, then is f a homeomorphism?

No. Counterexample: C -> C\{0}, z -> exp(z); C\0} -> C\{0}, z -> z^k (k>1) or any topological covering.

If U,V are open and U homeomorphic f(U), V homeomorphic f(V),
is not U \/ V homeomorphic to f(U) \/ f(V) = f(U \/ V) ?

No. Patch examples above.

--
Best wishes,
J.
.