Re: Local Homeomorphisms
- From: Jannick Asmus <jannick.news@xxxxxx>
- Date: Wed, 16 Apr 2008 10:32:17 +0200
On 16.04.2008 10:18, William Elliot wrote:
Let f:X -> Y be a local homeomorphism.
If X is connected, then is f a homeomorphism?
No. Counterexample: C -> C\{0}, z -> exp(z); C\0} -> C\{0}, z -> z^k (k>1) or any topological covering.
If U,V are open and U homeomorphic f(U), V homeomorphic f(V),
is not U \/ V homeomorphic to f(U) \/ f(V) = f(U \/ V) ?
No. Patch examples above.
--
Best wishes,
J.
.
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