Re: Local Homeomorphisms
- From: William Elliot <marsh@xxxxxxxxxxxxxxxxxx>
- Date: Thu, 17 Apr 2008 00:26:57 -0700
On Wed, 16 Apr 2008, Jannick Asmus wrote:
On 16.04.2008 10:18, William Elliot wrote:
Let f:X -> Y be a local homeomorphism.
If X is connected, then is f a homeomorphism?
No. Counterexample: C -> C\{0}, z -> exp(z);
f:C -> C\0, z - e^z
is a single counter example?
C\0} -> C\{0}, z -> z^kg:C\0 -> C\0, z -> z^k, k > 1
(k>1) or any topological covering.
is another counter example?
Don't understand "or any topological covering".
I'm to use f or g as an counter example?If U,V are open and U homeomorphic f(U), V homeomorphic f(V),
is not U \/ V homeomorphic to f(U) \/ f(V) = f(U \/ V) ?
No. Patch examples above.
"Patch" means to find U and V and show the patch U \/ V fails?
Not even if U and V are overlapping?
.
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