Re: Local Homeomorphisms
- From: William Elliot <marsh@xxxxxxxxxxxxxxxxxx>
- Date: Sun, 20 Apr 2008 02:37:10 -0700
On Sun, 20 Apr 2008, Jannick Asmus wrote:
On 20.04.2008 10:48, William Elliot wrote:Never heard that expression for subspaces.
On Fri, 18 Apr 2008, Jannick Asmus wrote:
On 18.04.2008 12:13, William Elliot wrote:
What's the trace topology?
... the induced topology on a subset, cf., e.g.,
http://en.wikipedia.org/wiki/Subspace_topology.
Google might become your friend one day. ;)It was once. Now Yahoo is my friend.
Is there any usage for the definition without f(U) being open?Another counter example is f:[0,1) -> S^1.Let f:X -> Y be a continuous bijection, X locally compact, Y Hausdorff.Certainly not: identity map (R,discrete topology) -> (R,norm topology).
Is f a local homeomorphism? Well clearly for all x, some
open U nhood x with U homeomorphic f(U), but is f(U) open?
Right.
It appears than in the notion of covering map, that the local
homeomorphism has f(U) being open, not by the definition of
local homeomorphism, but by the definition of covering map.
In other words
covering map --> local homeomorphism with open local images.
This is just convention - as I said already.
They were until they sold their soul to the stock market.What's the definition of HTH?Some compact K with x in int KConvention - like "nhood". I do not want to argue about something like
f:int K -> Y closed continuous bijection.
int K homeomorphic f(int K)
Why is f(int K) open, or is it?
HTH.HTH ?
this. ;)
Google should become your friend.
Ever since then I've been removing bookmarks to Google's services. They
are examples of 'new and improved' = 'isn't as nice and doesn't work as
good' and 'updates are worse than blind dates'.
Now Yahoo is my friend. Yahoo should become your friend.
.
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