Re: Lebesgue measure

On Apr 21, 3:44 pm, brown...@xxxxxxxxx wrote:
Let E be a dense set in R. If g:R-->R is a Lebesgue measurable
function on E, then is it a Lebesgue measurable function on R also?

If E = Q, the set of rational numbers, every subset
of E is measurable with the restriction of the algebra
of Lebesgue measurable sets to Q, so every function
g : R --> R restricts to a a measurable function Q --> R.

-- m
.