Re: Number with parameter...



"mina_world" <mina_world@xxxxxxxxxxx> writes:
"Tim Little" <tim@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:slrng1dp3r.92b.tim@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On 2008-04-29, mina_world <mina_world@xxxxxxxxxxx> wrote:
x^3 + y^2 = z^2.

A general rational solution, in terms of a parameter u, is:

(u^2 - x).x (u^2 + x).x
y, z = -----------, -----------
2.u 2.u
-----------------------------------------------------
Sorry. I don't know how to transfer with u. so, I need your advice.

It looks like you can pick any rational x and u, giving rational y and
z that satisfy the equation. Was that the question you had?

My question is...
How do you make y, z = ~, ~.

To make y you take u, square it, subtract x, multiply by x, and divide by 2u.
To make z you take u, square it, add x, multiply by x, and divide by 2u.

Phil
--
Dear aunt, let's set so double the killer delete select all.
-- Microsoft voice recognition live demonstration
.



Relevant Pages

  • Re: How inaccurate is a 555 or 7555 REALLY?
    ... on making a tiny quartz crystal divide down to 420hz in a tiny package ... Sine wave output preferred, but I think square ...
    (sci.electronics.design)
  • Re: Geometrically distributed random numbers on Rabbit 2000.
    ... >advice considering i know stuff all about math, ... >comes to probability and stats. ... >spam. ... divide the range by 5. ...
    (sci.electronics.design)
  • Re: Standard Deviation
    ... If you divide that value by N or N-1 you get the variance, which is s squared if you divide by N, or sigma squared if you divide by N-1. ... From that value again, you get the standard deviation by extracting the square root, which is either s or sigma. ...
    (borland.public.delphi.non-technical)
  • Re: New high speed rail line proposed
    ... towns/cities is to multiply the population of two towns, and divide by ... the square of the distance between them. ...
    (uk.railway)
  • Re: read/write at the same time
    ... Don't you only need to divide by primes from 3 to the prime below one- ... (primeth you've just tested) ... There is never any need to test with a number greater than the square ... root, there must be a corresponding factor smaller than the square root. ...
    (alt.comp.lang.borland-delphi)