Re: Number with parameter...
- From: Phil Carmody <thefatphil_demunged@xxxxxxxxxxx>
- Date: Tue, 29 Apr 2008 14:15:03 +0300
"mina_world" <mina_world@xxxxxxxxxxx> writes:
"Tim Little" <tim@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:slrng1dp3r.92b.tim@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On 2008-04-29, mina_world <mina_world@xxxxxxxxxxx> wrote:
x^3 + y^2 = z^2.
A general rational solution, in terms of a parameter u, is:
(u^2 - x).x (u^2 + x).x
y, z = -----------, -----------
2.u 2.u
-----------------------------------------------------
Sorry. I don't know how to transfer with u. so, I need your advice.
It looks like you can pick any rational x and u, giving rational y and
z that satisfy the equation. Was that the question you had?
My question is...
How do you make y, z = ~, ~.
To make y you take u, square it, subtract x, multiply by x, and divide by 2u.
To make z you take u, square it, add x, multiply by x, and divide by 2u.
Phil
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