Re: Isomorphism of quotient ring
- From: Jose <jose.fran80@xxxxxxxxx>
- Date: Mon, 05 May 2008 13:00:42 EDT
I told you, the only I think is the following:
h(t)= x + (...)
h(t^2)=y+ (...)
h(t^3)= z+ (...)
then I see that h f=id and fh=id
of course, I mean by f(x+(...))=t
Am I right ?
.
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