Re: factorial sequence proposal

"I.N. Galidakis" :
wugi wrote:

I really doubt that Mr. Sloane will bother emailing back to you a negative
response, or even a positive one for that matter. I don't think he has the
time,

I'm sure he hasn't, though he seems to suggest otherwise.

anyway. The way I check for my sequences, is to wait one-two months, until
they
finally show up in the list of new sequences. I received no notification
from
Mr. Sloane for my submissions.

The application procedure also
does (apparently) only take specific number examples; parametered
formulas seem out of question, ruling out god knows how many cases.

I don't think the OEIS is as much paranoid as you state. Did you use the
standard submission form that Mr. Sloane has available for upload?

That's the very one that seems to impose specific numbers, ruling out
parametred formulations. Not a matter of paranoyance, but of fill-in
facilities :-)

Another reason for failure might be that a(n) grows very rapidly and
Sloane
needs at least 5-6 terms from any new sequence. I don't think your a(n) is
very
friendly in that respect.

That's why I couldn't fill out specific-numbered examples ;-)
I also thought of this field of high-speed growing series (and ones starting
with, eg, googolplex), an interesting lot I'd say, but hard to specify their
members; doesn't OEIS mention such beasts?

And yet another reason your sequence didn't make it, might be that your
sequence
is really infinitely many sequences a(k,n), k,n\in N. Depending on the
arguments
k and n, you get many different sequences. For example:

a(k,1) = {1, 1, 1, ....}
a(k,2) = {2, 2, 2, ....}
a(k,3} = {3, 720, .2601218944e1747, ...}
a(k,4) = {4, 620448401733239439360000, ....}
....

That's why I spoke of a parametred family, or one with a seed n...
Surely there must be a lot of those, how does (or not) OEIS treat them?

A by-observation for the series above:
2 is apparently a unit seed (besides 1), as we get
2=2!=2!!=2!!!=....

Yes. The exact terminology you have in mind, is probably that of "fixed
point".

2 is a fixed point of your a(n). So is 1 in fact, since:

a(k,2) = 2, for all k\in N and a(k,1) = 1, again for all k\in N.

Thanks!

guido
http://home.scarlet.be/~pin12499


.

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