Re: 4=3 A maths joke



In article <mn.82397d8553dc03ca.22155@xxxxxxx>,
"Philippe 92" <nospam@xxxxxxxxxxxx> wrote:

Michael Press a écrit :
In article
<dc9e218c-9429-48e2-a05b-d5ab1dfcb59a@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Tonico <Tonicopm@xxxxxxxxx> wrote:

On May 15, 9:02 am, Albert <albert.xtheunkno...@xxxxxxxxx> wrote:
LOL This took me 5 minutes to work out what was wrong to my friend and
it was hilarious.
a+b=c where c > a and c > b
4a-3a+4b-3b = 4c-3c
4a+4b-4c=3a+3b-3c
4(a+b-c)=3(a+b-c)
4=3

Where's the flaw?

*****************************************************************

Want a slightly (VERY slightly) less boring and less known "hoax",
which at least uses some basic calculus? Here:

Let n be a natural number (non-zero, to be sure). As we all know, n^2
= n*n, and the right side can be put as n + n +....+n (n times), so:

** n^2 = n + n +...+ n (n times). Now evaluate the derivative in both
sides, using the well known rule for the sum:

** 2n = 1 + 1 +...+ 1 (n times) = n , and thus
^^^^^^^^ ^^^^^^^^^^^^^
OK Bzzzzzzzzzzzzzzzzzzzzt!

should be 1 + 1 +...+ 1 (n times) + n (1 times)


Same bad answer as amy666.

the "n times" does **not** states for a multiplication but just
says there are n terms in a **sum**, each one equal to n.

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The derivative of "n + n + ... + n (n times)" just doesn't exist !

Yes it does. My answer stands.

what is "/pi + /pi + /pi ... + /pi (/pi times)" in your mind ???

`/pi' is a term, right?
Answer: /pi * /pi.

d/(d/pi) (/pi + /pi + ... + /pi (/pi times) =
1 + 1 + ... + 1 (/pi times) + /pi (1 times) = 2 * /pi.

How many terms are there ? /pi ???

Yes.

In other words you can say n^2 = n + n + ... + n (n times) only for
n *integers*, not for real numbers in /R,

Yes, I can, and without fear of consequences.

hence you can't calculate
any derivative at all.

I just did.

In the case when the derivative of the left side has meaning,
the derivative of the right side has meaning.

n^2 = n + n + ... + n (n times)

is taken to be meaningful.
If the answer to the original puzzle is

"`n^2 = n + n + ... + n (n times)'

is not meaningful", then you are welcome to it.
I gave a mathematically sound answer based on
the presumption that the _question_ is meaningful.

--
Michael Press
.



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