Re: Very simple question/paradox about integrals.

An integral sign without any bound doesn't have any proper sense.

Try it with :

int_g(a)^g(b) f(u)du=int_a^b f(g(x))g'(x)dx and u=g(x)


On 24 mai, 13:03, gtsav...@xxxxxxxxx wrote:
The following is any bound doesn't have any proper sensetrue:http://i215.photobucket.com/albums/cc34/Crocodile13/we1.jpg

So after applying it to a function we have:http://i215.photobucket.com/albums/cc34/Crocodile13/we2.jpg

Something is clearly wrong. There is something, somewhere, that i
miss. But where is it?

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Sorry that you have to copy and paste the images to be shown but i
don't know if IMG tags work here.
Test(ignore it):
[IMG]http://i215.photobucket.com/albums/cc34/Crocodile13/we2.jpg[/IMG]
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