Re: Intersection of Ellipsoid and a Plane in space
- From: miki <miki.livne@xxxxxxxxx>
- Date: Wed, 28 May 2008 06:02:19 -0700 (PDT)
On May 28, 2:31 pm, Mariano Suárez-Alvarez
<mariano.suarezalva...@xxxxxxxxx> wrote:
On May 28, 9:26 am, miki <miki.li...@xxxxxxxxx> wrote:
Hello All,
Can any one come up with a closed-form to the following problem...
This is a symmetrical Ellipsoid
x^2+y^2 z^2
----------- + ----- = 1
a^2 b^2
This is a general equation for a plane in space which pass through the
origin
Ax+By+Cz=0
My question is what is the equation of the two dimensional Ellipse
which is being created
by the intersection of the Ellipsoid and the plane.
I got something of the form
x^2 y^2 r^2 * x*y
------- + ----- + ------------ = 1
s^2 t^2 p^2
where s,t,r,p are some constants.
Notice that this is not the equation of the intersection
of the ellipse and the plane, because in R^3
this is the equation of a *surface*. At most, this is
the equation of the projection of that intersection
to the x-y plane.
The problem is, I dont get an Ellipse in its known form.
You have not told us what is the `known form'.
What can I do?
Find out of what the general equation of an ellipse is.
-- m- Hide quoted text -
- Show quoted text -
Sorry,
The general form I'm looking for is
x^2 y^2
--- + --- = 1
v^2 w^2
Actually, what I'm looking for is v and w.
Thanks
.
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