Re: A Formula for Pi
- From: José Carlos Santos <jcsantos@xxxxxxxx>
- Date: Fri, 20 Jun 2008 08:50:29 +0100
On 20-06-2008 7:16, Maury Barbato wrote:
I found in the book "The Penguin Dictionary of
Curious and Interesting Numbers" by Wells the following formula involving pi
(pi - 3)/4 =
= sum_{k=1 to infty}[(-1)^(k+1)]/[2k*(2k+1)*(2k+2)]
Is there anybody who knows a proof of this wonderful
series?
You already got a reply. I only want to remark that the formula is
equivalent to
pi - 3 = sum_{k = 1 to oo}(-1)^{k + 1}/(k(2k + 1)(k + 1)
= sum_{k = 1 to oo}(-1)^{k + 1}/(1^2 + 2^2 + ... + k^2).
Best regards,
Jose Carlos Santos
.
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