Re: A Formula for Pi
- From: Maury Barbato <mauriziobarbato@xxxxxxxx>
- Date: Fri, 20 Jun 2008 11:57:49 EDT
Jose Carlos Santos wrote:
On 20-06-2008 7:16, Maury Barbato wrote:
I found in the book "The Penguin Dictionary ofwonderful
Curious and Interesting Numbers" by Wells the
following formula involving pi
(pi - 3)/4 =
= sum_{k=1 to infty}[(-1)^(k+1)]/[2k*(2k+1)*(2k+2)]
Is there anybody who knows a proof of this
series?
You already got a reply. I only want to remark that
the formula is
equivalent to
pi - 3 = sum_{k = 1 to oo}(-1)^{k + 1}/(k(2k +
2k + 1)(k + 1)
= sum_{k = 1 to oo}(-1)^{k + 1}/(1^2 +
+ 1}/(1^2 + 2^2 + ... + k^2).
Best regards,
Jose Carlos Santos
A little slip. We have
pi - 3 =
sum_{k = 1 to oo}(-1)^{k + 1}/[k(2k+ 1)(k + 1)]=
= (1/6)* sum_{k = 1 to oo}(-1)^{k + 1}/(1^2 + 2^2 + ... + k^2)
It's a very very beautiful formula!
Thank you for your attention.
My Best Regards,
Maury Barbato
.
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