Re: "Near to" zero eigenvectors

On Jun 20, 12:25 pm, Richard Hayden <r.hay...@xxxxxxxxx> wrote:
Hi,

If I have a real n x n matrix A and some real n-vector x, such that

A x = a

can I always find a vector x' (dependent on a), such that A x' = 0 and
| x - x' | -> 0 as |a| -> 0?

Thanks,

Richard.

I, too, have trouble (I believe) understanding your question as,
perhaps, revealed by the following question:

Why isn't x'=a+x an answer?
.

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