tetration and logaritms
- From: amy666 <tommy1729@xxxxxxxxxxx>
- Date: Wed, 09 Jul 2008 14:59:28 EDT
we all know the taylor series for log(1+x) which holds for all real x between -1 and 1.
this series starts with 0 + x - x^2/2 + ...
and from looking at the first terms of this taylor series we see that we can get series reversion which of course gives exp(x) - 1.
fractional iterations can be done for exp(x)-1 since its a taylor series with f(0) = 0. ( and its unique )
and thus also for log(1+x) , either directly since log(1) = 0 or from the series reversion of the fractional iterations of exp(x)-1.
so we can compute f(f(1+x)) = log(1+x) (*)
( for x between -1 and 1 )
set v = x+1 for v between 0 and 2
f(f(v)) = log(v)
now we can thus compute the half-iterate of the log function.
(*) beware f(f(x+1)) is a taylor series in x but you need to convert to a taylor series in x+1 !!
use the substitution x = w-1 and the binomial theorem to compute it.
thus for v between 0 and 2 we can compute f(v) and
f(v) is the half iterate of log(v).
to compute the half iterate of e^v , simply use
exp(f(v)).
thus semi-exp(1) = exp(f(1))
despite f(2.71828) is undefined since e = 2.71828..
is larger than 2 we can now also compute semi-exp(e)
semi-exp(e) = exp(exp(f(1)).
all of this of course shows tetration does exist ;
unique continu iteration of exp(x) !!
tetration is by this construction smooth ...
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analytic too ?
natural question ; what about complex iterations ?
if a function is smooth but complicated
if analytic , we can apply analytic continuation.
if not analytic , how do we do a continuation ?
( i assume doing the analytic continuation of its inverse function , and that this works for tetration but im not sure , as for the general case if this does not work i dont know )
but note that i dont require tetration to be defined for complex numbers.
why not ?
an example : exp(x) is the continu iteration of e*x.
an iteration of a function is not suppose to have period.
( think about it ! )
e.g. sine seems like an iteration of sqrt(1-x^2)
but look at the zero's of sin(q) = 1/5.
the zero's are not periodic , thus the iterations at the values 1/5 are not always the same iteration !!
thus sine does not represent a unique continue iteration.
exp(x) is on R since exp(x) is monic.
however exp(x) has a period too ; 2pi i !
thus in the complex sence exp(x) is not a unique continue iteration !!
THUS any function that has a period is not a unique continue iteration.
( or that function + some complex constant as demonstrated by sine )
i dont think any smooth function exists that is a unique continue iteration (in the complex sense ) apart from a*z + b.
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this makes tetration a computable function , however the goal of a series expansion is still not reached.
since my solution is unique maybe we should drop the restriction of analytic on R+ to smooth ( C oo ).
( however it might be analytic on R+ afterall )
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pentation still seems out of reach ...
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regards
tommy1729
.
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