Re: Why does everyone do it?

On Aug 12, 3:07 am, Han de Bruijn <Han.deBru...@xxxxxxxxxxxxxx> wrote:
Mike Kelly wrote:
Han de Bruijn wrote:

David C. Ullrich wrote:

I _can_ prove that |P(A)| > |A|. And the proof is very simple.

Sure. But what has _this_ to do with the uncountability of the reals ?

Do you _really_ not know? Are you just playing dumb?

No. I *am* dumb. Okay?


Ah. So then why bother going at this again and again if you're
so dumb? Umm...

There is a bijection between P(N) and R. So |R| = |P(N)|.

So |P(N)|>|N| implies |R| > |N|.

What a wonderful world ..


So does that mean you admit it is so?
.

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