Re: Quartic Equation: do you know a procedural way to solve it ?
- From: iakko <iacopo.palazzi@xxxxxxxxx>
- Date: Fri, 22 Aug 2008 07:18:25 -0700 (PDT)
On Aug 22, 4:09 pm, "Dave L. Renfro" <renfr...@xxxxxxxxx> wrote:
Using Helmut Richter's example, if instead you wanted the
solutions to x^2 + x - 1 = 0, would you rather see something
like (-1/2) +/- (1/2)(sqrt 5) as the output or see something
like 0.61803398874989, -1.61803398874989? [High school students
reading this might want to see if you can figure out why
the expansions to the right of the decimal place agree.]
Dave L. Renfro
The second one, as I'm looking for collision points in 3D space. If I
get complex roots, then I know that there is no collision at all.
.
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