Re: -- group idenitities of the form (xy)^k = x^k y^k

In article <29559831.1221765803700.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
amy666 <tommy1729@xxxxxxxxxxx> wrote:
Tim Smith wrote :

In article
<0er3d4l4ccjssm81cbobt37q5eejffog1t@xxxxxxx>,
quasi <quasi@xxxxxxxx> wrote:

[...]

If G is a group in which (ab)^i = a^i b^i for
for three consecutive
integers i for all a, b in G, show that G is
is abelian.

[...]

hmm

doesnt that proof assume associativity ?

Calling it a "group" kind of gives the game away in the first place in
that regard.

--
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"It's not denial. I'm just very selective about
what I accept as reality."
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Arturo Magidin
magidin-at-member-ams-org

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