Re: Farmer Brown's conjecture

On Oct 7, 10:32 am, "T.H. Ray" <thray...@xxxxxxx> wrote:
One multiplied by one is two.
One instance of one is one.
One times one is one.

The square root of two is one.

If the square root of two were one, the square root
of four would also be one, by your reasoning. After
all, one instance of four is one--right? One times four
is one. One instance of four cannot be four instances;
otherwise, 1=4.



No you are mistaken. I am saying multiplied by, not instance of.

Mr. Barnum peered with awe into his microscope and proclaimed "They
are multiplying!"
"The cells! They are multiplying by cell division. One cell multiplied
one time into two cells I saw it with my own eyes"

One cell multiplied into two cells, the cells went forth and
multiplied.

Once multiplied into two, and the reverse, one cell divided into two,
and since one cell multiplied into two, one multiplied one time equals
two, hence the square root of two is one.

That is my proof and I would love to see your proof, that one
multiplied one time equals one.
.

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