Re: D is integral domain and D[t] is PID, how to show D is a field
Luke Wu <LookSkywalker@xxxxxxxxx> wrote:
D is an integral domain (commutative ring with no zero divisors).
D[t] is Principal Ideal Domain (all ideals are generated by single
elements of D[t]). Then how can one show that D is a field?
If not, consider (d,t) for nonunit d in D.
And is there a common name for ideals generated by 2 elements
2-generated ideals.
--Bill Dubuque
.
Relevant Pages
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(sci.math) - Re: Why is it called a Divisor?
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