Re: sine and modulus ?
- From: quasi <quasi@xxxxxxxx>
- Date: Sun, 19 Oct 2008 19:04:13 -0400
On Sun, 19 Oct 2008 15:54:30 EDT, amy666 <tommy1729@xxxxxxxxxxx>
wrote:
quasi wrote :
On Sun, 19 Oct 2008 07:17:44 EDT, amy666
<tommy1729@xxxxxxxxxxx>
wrote:
im thinking about a sine defined for modulusalgebra.
Sounds like fun.
sin(a) mod p = b mod ptaylor series expanded at 0 and mod p.
cos(a) mod p = c mod p
b^2 + c^2 = 1 mod p
where the sine and cosine can be computed by their
But regardless of the modulus, the coefficients of the
Taylor series are eventually all undefined (division by 0).
huh ?
mod p is chosen such that all elements have multiplicative inverses ...
All _nonzero_ elements have multiplicative inverses.
What is the Taylor series for sin(x)? (over the reals)
Now try it (mod 2). Next try (mod 3).
Do you see a problem?
quasi
.
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