Show a sequence does not have a limit
- From: Cliff MacGillivray <cliff@xxxxxxxxxx>
- Date: Mon, 20 Oct 2008 23:19:38 -0400
Show x_n=1 + 1/sqrt(2) + ... + 1/sqrt(n) does not have a limit using the
Cauchy Criterion.
Solution:
If n>m then we have s_n - s_m =
=1/sqrt(m+1) + 1/sqrt(m+2) + ... + 1/sqrt(n)
> 1/sqrt(n) + 1/sqrt(n) + ... + 1/sqrt(n) = (sqrt(n) -
sqrt(m))/sqrt(n) since we have n-m 1/sqrt(n) terms
=1 - (sqrt(m) / sqrt(n))
So, if we choose n=4m than we have s_4m - s_m > 1/2 . Thus the sequence
cannot be cauchy since we cannot choose an aribitary h >0 such that for
any n,m |s_n - s_m| < h and so it does not have a limit.
Correct? Wrong? Any Mistakes?
.
- Follow-Ups:
- Re: Show a sequence does not have a limit
- From: William Elliot
- Re: Show a sequence does not have a limit
- Prev by Date: Re: power series expansion for exp(x/(1+x))
- Next by Date: zoo 365 tube - Free Video
- Previous by thread: Counting Dance Couples
- Next by thread: Re: Show a sequence does not have a limit
- Index(es):