Re: Simplify infinite series with Sines???

On Mon, 17 Nov 2008 07:58:39 -0800 (PST), TechnoBuddhist
<google@xxxxxxxxxx> wrote:

Sorted!!

I just found this site;
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=algebra&s2=simplify&s3=advanced

for 2 of my terms 2 and 3; it gives

(1/6)sin^2(x?)

and for 3 terms 2,3,4,5; it gives

(1/120)sin^4(x?)

Looking at my graphs now, the waves coincide perfectly!! so problem
solved!! unless there is something else I should know?

This is the expression you gave in your first posting:

sin((x*pi)/2) * sin((x*pi)/3) * sin((x*pi)/4) * sin((x*pi)/5) *...*
sin((x*pi)/n) ; for 2<=x<=n

Now are you saying
sin((x*pi)/2) * sin((x*pi)/3) = (1/6)sin^2(x pi) ???

Which is correct ... the original expression, or the 'solution' you
just now posted? They can't both be right.

Notice that
.

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