Re: Lagrange Polynomial, Taylor's series, e^ix

On Jan 7, 9:53 am, Nimo <azeez...@xxxxxxxxx> wrote:
1Q)  If the equation is like this
       e^ix-100=0
       how to find x value ?
       Is it possible to do that ?

e^(ix) = 100

but also

e^(i(x + 2 pi n)) = 100
by periodicity
(this is to reveal the multivalued inversion)

take lns

i(x + 2 pi n) = 100

x = -100i - 2 pi n
for all integers n

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