Re: Lagrange Polynomial, Taylor's series, e^ix
- From: Matt <matt271829-news@xxxxxxxxxxx>
- Date: Thu, 8 Jan 2009 06:14:34 -0800 (PST)
On Jan 8, 1:53 pm, Matt <matt271829-n...@xxxxxxxxxxx> wrote:
On Jan 8, 10:06 am, Nimo <azeez...@xxxxxxxxx> wrote:
On Jan 8, 1:06 pm, galathaea <galath...@xxxxxxxxx> wrote:
On Jan 7, 9:53 am, Nimo <azeez...@xxxxxxxxx> wrote:
1Q) If the equation is like this
e^ix-100=0
how to find x value ?
Is it possible to do that ?
e^(ix) = 100
but also
e^(i(x + 2 pi n)) = 100
by periodicity
(this is to reveal the multivalued inversion)
take lns
i(x + 2 pi n) = 100
x = -100i - 2 pi n
for all integers n
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
galathaea: prankster, fablist, magician, liar
thanks for the help
what about 3Q) ?
is it confusing
-=-=-=-==--=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
/*In a single line the problem would be like this*/
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Given Taylor's polynomials for a function f(x) in [a,n]
if taylor's polynomials at all points are given
T(a),T(b),T(c).......T(n)
how to construct the precise function.
what should I do ?
Ignoring for these purposes issues to do with convergence or non-
convergence, the Taylor series (I assume that's what you mean by
"Taylor's polynomial") at any point defines the *whole* function. So,
you only need one of them, say T(a). Given T(a), constructing f(x) may
be anything from trivial to extremely difficult, depending on whether
the series has a finite or infinite number of terms, whether you have
the coffecients of the series symbolically in terms of a or only
numerically, and whether the series is in a plain or obfuscated form.
Oops, sorry, scratch that reply... I guess you mean you have the terms
of the Taylor series up to a certain point, but no further.
.
- References:
- Lagrange Polynomial, Taylor's series, e^ix
- From: Nimo
- Re: Lagrange Polynomial, Taylor's series, e^ix
- From: galathaea
- Re: Lagrange Polynomial, Taylor's series, e^ix
- From: Nimo
- Re: Lagrange Polynomial, Taylor's series, e^ix
- From: Matt
- Lagrange Polynomial, Taylor's series, e^ix
- Prev by Date: Re: I don't want a tangent, but e^ix
- Next by Date: Re: Lagrange Polynomial, Taylor's series, e^ix
- Previous by thread: Re: Lagrange Polynomial, Taylor's series, e^ix
- Next by thread: Re: Lagrange Polynomial, Taylor's series, e^ix
- Index(es):
Relevant Pages
|
