Restriction of Linear Operator
- From: jbergmanster@xxxxxxxxx
- Date: Sat, 10 Jan 2009 16:00:04 -0800 (PST)
I am doing some self-study out of a Linear Algebra text.
I am trying to prove one of the questions and it seems obvious so I
wonder if I am missing something.
The question asks to prove
Given a operator T on the vector space V, and a T-invariant subspace W
that an eigenvector of Tw (restriction of T to W) is also an
eigenvector of T and
has the same eigenvalue.
However I thought the restriction of T was just limiting the domain to
W so that Tw(v) = T(v) for v in W. What more is there to say?
.
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