Re: More trigonometric equations!!!
- From: Albert <albert.xtheunknown0@xxxxxxxxx>
- Date: Thu, 29 Jan 2009 19:07:32 -0800 (PST)
Thanks to everyone so far! You're really helping me learn this stuff
on my own + with a little guidance.
:)
Example 8. Solve the following equation for 0 degrees <= x <= 360
degrees:
cos^2(x) + 5sin(x)cos(x) = 3
I've tried dividing by A square of a trig function. I've also tried
substituting 3 = 3sin^2(x) + 3cos^2(x). But what I've found is that
the term involving sin(x)cos(x) is always present and prevents any
quadratic equation from appearing. What should I next try to do?
.
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