Re: -- polyhedron with non-convex faces
- From: Michael Press <rubrum@xxxxxxxxxxx>
- Date: Fri, 06 Mar 2009 21:36:32 -0800
In article <slrngr2u7r.c79.tim@xxxxxxxxxxxxxxxxxxxxxxxxxx>,
Tim Little <tim@xxxxxxxxxxxxxxxxxx> wrote:
On 2009-03-06, Brian Chandler <imaginatorium@xxxxxxxxxxxxx> wrote:
Ingenious! But it seems slightly unsatisfactory for the polyhedron to
be a torus (topologically).
Well, yes. It was just the first example I thought of.
So I _think_ this is a decahedron with six "dart" faces, two
double-dimpled triangles and two single-dimpled triangles.
Yes, that would certainly work. Or for more symmetry, do the same to
opposite vertices of a cube.
I'm sure I remember seeing a model of intersecting tetrahedra
somewhere, having only *congruent* non-convex faces. ... Aha!
http://en.wikipedia.org/wiki/File:Compound_of_five_tetrahedra.png
Five cubes.
<http://en.wikipedia.org/wiki/File:UC09-5_cubes.png>
These compounds have convex faces.
Here is a (regular) polyhedron with non-convex faces.
<http://en.wikipedia.org/wiki/File:Great_stellated_dodecahedron.png>
--
Michael Press
.
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