---- --- ---- Conditional non integer solutions




Consider the following two equations for the given conditions.

u = [(2^n)t]^(1/k) (1) v = [(2^m)f]^
(1/2k) (2)

Conditions: m, n, t, f are integers each > 0, f and t are odd, prime k
3
Given situation: if u is a non integer then v is also a non integer.

Assertion: If v is a non integer then u is also a non integer.

Any comments and reference about the correctness of the Assertion will
be appreciated.
.



Relevant Pages

  • Re: Which Is The Better Approach To Working With Javascript?
    ... HTML-embedded class now dominated by JSP, ASP, and PHP. ... make that assertion. ... Odd that ..I am sure we were running CGI based on scripts and PERL and C earlier than that, ...
    (comp.lang.php)
  • Re: ----- ----- Prime number
    ...  v is even and u is odd, b is even and a is odd, k is a prime> 5. ... quantities are relatively prime ... Assertion: does not have any solution. ... is inconsistent. ...
    (sci.math)
  • Re: ----An Assertion in Trigonometry
    ... A, B, b are rational each> 0 but none is a pefect ... Odd k> 3 ... Assertion: a is not a perfect square. ...
    (sci.math)
  • Re: A few novice questions
    ... Robert Adsett schreef: ... That seems a rather odd assertion... ... Considering I'm about the same age as the 4000 series, I guess the odds are pretty high. ...
    (comp.arch.embedded)
  • ----- ----- Prime number
    ... v is even and u is odd, b is even and a is odd, k is a prime> 5. ... quantities are relatively prime ... Assertion: does not have any solution. ... Any comment about the correctness of the assertion will be highly ...
    (sci.math)

Quantcast