Re: sum of roots of unity



On Jun 17, 2009 at 9:32 PM CT, Rob Johnson wrote:

In article
<3279063.10397.1245290228761.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
Narcoleptic Insomniac
<i_have_narcoleptic_insomnia@xxxxxxxxx> wrote:
On Jun 17, 2009 at 6:22 PM CT, Rob Johnson wrote:

In article
<0ac4b3e9-7b7b-409e-99f5-1d4d9526a9e4@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"oferlock@xxxxxxxxx" <oferlock@xxxxxxxxx> wrote:
this might be trivial, but I am a bit confused:
let N be some composite integer. Let t be some
integer from 1 to N-1. then, is the following
true for all such t?
sum_{k in {0..N-1}} e^{i pi t k/N} = 0
(note we do not necessarily have powers of a
primitive Nth roots of unity here)

There have been a few approaches posted here, but I
am surprised that what I think is the simplest
explanation has not appeared yet:

The sum of the roots of a monic polynomial is
negative of the coefficient of the penultimate term.

Thus, the sum of the roots of x^N - 1 is the
negative of the coefficient of x^{N-1}, namely 0.

Actually, this is exactly what I said a few days ago...
just in a more general sense using elementary symmetric
polynomials.

I'm guessing my posts are being filtered? Rob?

No, they are there, I just thought that you were doing
something more. I see that your post just looked more
complex because you pretty much rederived the fact that
I simply stated.

Ahhhh, I see ^_^ Well, assuming that the OP missed a
factor of 2 (as Achava Nakhash pointed out) and actually
meant to ask if the summation

p_t = sum_{k = 0}^{N - 1} e^{2 pi i k t / N} = 0

...for all 1 <= t <= N - 1, then equating the coefficients
of the "penultimate" term only shows that p_1 = 0. To show
that p_t = 0 for the remaining values -- using this method
of comparing coefficients -- I believe that the values of
all elementary symmetric polynomials must be found first
(an easy task, as they are just the other coefficients).
Given all of the ESPs, the values of all of the power
sums, p_t, can be found using an identity from Newton...

It seems a lot less simple, though no less valid,
when you include the derivation.
.



Relevant Pages

  • Re: sum of roots of unity
    ... On Jun 17, 2009 at 6:22 PM CT, Rob Johnson wrote: ... let N be some composite integer. ... The sum of the roots of a monic polynomial is negative ... of the coefficient of the penultimate term. ...
    (sci.math)
  • Re: ambiguities
    ... >2) polynomial can only have terms with powers that are positive ... Nobody thinks polynomials can only have positive powers: ... The constant term is both a term and a coefficient. ...
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  • Re: hahn banach
    ... "classical" is the space of all polynomials over the ... leading coefficient is positive, ... are those of the Statistics Department or of Purdue University. ... Herman Rubin, Department of Statistics, Purdue University ...
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    ... the number and arrangement of any integer superstable fixed points of f? ... What I cannot find are any higher polynomials where there are three or more ... Whenever I have tried constructing equations and solving them there has ... always resulted at least one coefficient that will not reduce to integer ...
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  • Re: Is there a more elegant way to populate a linked list ?
    ... >accepts polynomials as pairs of values from a text file and is included ... >coefficient and the second number represents the polynomial power. ... two values per loop iteration, ...
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