Re: JSH: ?
- From: JSH <jstevh@xxxxxxxxx>
- Date: Tue, 30 Jun 2009 20:33:43 -0700 (PDT)
On Jun 30, 8:14 pm, ab <hobk...@xxxxxxxxx> wrote:
On Jul 1, 11:38 am, JSH <jst...@xxxxxxxxx> wrote:
Reduce it to an isomorphism like you claim you did with what I was
replying to, which you deleted out.
What year are you? My guess is you are a 2nd year math undergrad.
___JSH
I factorised your other polynomial into non-units across polynomials
with integer co-efficients, rather than "reduced it to an
isomorphism", whatever that means in this context.
7(175x^2 - 15x + 2) is already factorised into non-units across
polynomials with integer co-efficients. So could you explain
*precisely* what you want me to do with it beyond that?
That's only half the story, you forgot the equals and everything that
comes after:
7(175x^2 - 15x + 2) = (5b_1(x) + 7)(5b_2(x)+ 2)
where
b_1(x) = a_1(x) and b_2(x) = a_2(x) + 1
and the a's are roots of
a^2 - (7x-1)a + (49x^2 - 14x) = 0.
How does the mathematics determine how to multiply that 7 out of
infinity?
I'm a maths graduate.
Think so?
James Harris
.
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