Re: FOUR COLOR THEOREM
- From: Musatov <marty.musatov@xxxxxxxxx>
- Date: Wed, 15 Jul 2009 16:58:11 -0700 (PDT)
Musatov wrote
bill wrote:
The Heawood four-color graph is a 25-node planar graph that tangles
the Kempe chains in Kempe's algorithm and thus provides an example of
how Kempe's supposed proof of the four-color theorem fails.
The example present a coloring of the graph which experiences an
impasse with the coloring of
the 25th vertex. The impasse is due to the following situation:
V_25 is adjacent to;
V_1 which is Y
V_2 which is R
V_3 which is B
V_4 which is R and
V_5 which is G.
Suppose, that instead of trying to color v_25, we remove it and
install an edge between v_2 and v_4. A proper 4-coloring of gthe
resulting graph demands that v_2 and/or v_4 be recolored.
A recoloring of v_2 and/or v_4 will result in two cases;
1) The set of vertices v_1 thru v_5 is 3-colorable. Then the
complete graph, with v_25 will
be 4-colorable, or
2) The set of vertices v_1 thru v_5 is not 3-colorable.and the
impasse still exists. But there
are still two vertices with the same color. An edge can be
installed between these two
vertices and the prolem returns.
Let G be the graph with v_25 removed. In essence,
3) Any coloring of G that does not permit a 4-coloring of the
complete graph can be
confounded by a strategically placed edge
4) G can be recolored so as to negate the impact of such an edge
and still deny a
4-coloring to the complete graph..
The cycle of 3), 4), 3), etc. will continue indefinitely unless there
is a configuration
of G that permits a 4-coloring of the complete graph.
IMMHO, the recoloring of G will eventually lead to a proper 4-coloring
of the complete
graph.
regards, Bil J
Thank you
.
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- FOUR COLOR THEOREM
- From: bill
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