Re: integral(0,inf){ t k exp(-kt) }dt
- From: William Elliot <marsh@xxxxxxxxxxxxxxxx>
- Date: Mon, 10 Aug 2009 01:41:36 -0700
On Sun, 9 Aug 2009, David C. Ullrich wrote:
(i) Suppose that F(x,t) and the partial F_x(x,t) areDoes this mean that (i) can be extended to
continuous in the compact rectangle [a,b] x [c,d].
Define
f(x) = int_c^d F(x,t) dt (x in [a,b]).
Then f is differentiable on (a,b), with
f'(x) = int_c^d F_x(x,t) dt.
That's not enough for the current problem because
we're taking an integral from 0 to infinity. But here's
something else from calculus:
(ii) If f_n is differentiable, f_n -> f pointwise and
f_n' -> g uniformly then f is differentiable and f'=g.
Now let f_n = the integral from 1/n to n in the original
problem. (i) shows that f_n' is what it should be and then
you can use (ii) to show that f' is what it should be.
(ii) Suppose that F(x,t) and the partial F_x(x,t) are
continuous in the sigma compact rectangle [a,b] x [c,oo)
Define
f(x) = int_c^d F(x,t) dt (x in [a,b]).
Then f is differentiable on (a,b), with
f'(x) = int_c^oo F_x(x,t) dt.
.
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