Re: An inequality involving e
 From: rob@xxxxxxxxxxxxxx (Rob Johnson)
 Date: Fri, 18 Dec 2009 15:25:47 +0000 (UTC)
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In article <92d718f6b4ab4e00a244ba6ca43555ff@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
TCL <tlim1@xxxxxxx> wrote:
Let n be an integer >1. From the graph it is clear that
e^{x} > (1  x/n )^n for all x in the interval 1<= x <= n
I have a little hard time trying to prove it. Maybe some of you here
have a clever idea.
Hint: Take nth roots of both sides, then all you need to show is that
e^{t} > 1  t for 0 < t <= 1
Rob Johnson <rob@xxxxxxxxxxxxxx>
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