Re: Exact solution of y' ' (x) - k*y(x)*( 1 - (y ' (x) )^4) = 0
- From: C W <sylvester7@xxxxxxxxxxxxxxx>
- Date: Mon, 27 Mar 2006 10:32:40 GMT
probleman wrote:
Hi;
I tried all the methods that I know and learned yet, but I could not
find it. If it is possible I want to know whether there exists an exact
solution of the equation y' ' (x) - k*y(x)*( 1 - (y ' (x) )^4) = 0 or
not.
Thanking you in advance and I'm looking forward to hearing from you
soon... Ali KONURALP
Your equation also satisfies :
(y')^2 = 1/(-c^2+exp(k*y(x)^2))/(c^2+exp(k*y(x)^2))*(c^4+exp(k*y(x)^2)^2) for
some constant c.
Chris
.
- References:
- Exact solution of y' ' (x) - k*y(x)*( 1 - (y ' (x) )^4) = 0
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