Re: Dependence of wave length of sound waves and light waves

From: Jim Greenfield (greenfield_7_at_hotmail.com)
Date: 11/29/04 

Date: 28 Nov 2004 21:49:52 -0800

The Ghost In The Machine <ewill@sirius.athghost7038suus.net> wrote in message news:<pomp72-kja.ln1@sirius.athghost7038suus.net>...
> In sci.physics, Jim Greenfield
> <greenfield_7@hotmail.com>
> wrote
> on 28 Nov 2004 01:19:43 -0800
> <3c4afb26.0411280119.7dcb5fbd@posting.google.com>:
> > cyber_khan2u@hotmail.com (Khalid Shakeel Babar) wrote in message news:<1b1b8c4a.0411260658.711321d8@posting.google.com>...
> >> Sometimes wave length of a wave is misunderstood as a constant
> >> quantity. But it is not constant. It changes with the medium of
> >> propagation.
> >> Let us take the example of sound waves.
> >> As velocity = wave length x frequency .
> >> But velocity of sound waves increases when they travel through the
> >> water(denser medium) compared to air, as the frequency is constant, so
> >> according to above formula the wave length of sound waves is increased
> >> in water. So, it proves that wave length is not a constant quantity.
> >> Now, Let us take the example of light waves.
> >> As velocity = wave length x frequency .
> >> But velocity of light waves decreases when they travel through the
> >> water, as the frequency is constant, so according to above formula the
> >> wave length of light waves is decreased in water. So, it proves that
> >> wave length is not a constant quantity.
> >
> > You're getting there!
> > In many cases the observed change in frequency (Doppler shift) of
> > light, is NOT due to a change in wavelength, but in a change in c!
> >
> > Jim G
> > c'=c+v
>
> You of course have an experiment showing this, right?
>
> Please, details, I want the details! :-)

Cases of redshift: (changed c may be due to mass of source, OR its
motion).

Radio: receiving antenna has to be tuned differently for out-going and
in-coming spacecraft, although they are broadcasting at the SAME
frequency.

Forget both for awhile!
Let's ask Cassini to send a pulse with the source location when it is
travelling away from earth; then when it is travelling towards. We
expect roughly 1 second difference. How much will that cost?? (F*A*)
What are the chances of DHR's (with the money and control to make it
happen)
getting it done???????????/...........and kill the golden goose? Not
likely!

Relevant Pages