Re: projection question
- From: <salmonegg@xxxxxxxxxxxxx>
- Date: Mon, 31 Oct 2005 19:01:15 GMT
On 10/31/05 2:11 AM, in article dk4qoh$qio$1@xxxxxxxxxxxxxxxxxxxxx, "Dave B"
<magnatomdb@xxxxxxxxxxxx> wrote:
> Hi Folks,
>
> I am a hospital physicist and I have been asked to build a projection
> system into one of our hospitals scanners. However, its been a good
> number of years since I have done any optics, so I am here for some help.
>
> I have been asked to build a projection system similar to that described
> in this paper
> (http://doi.wiley.com/10.1002/(SICI)1522-2586(200002)11:2%3C223::AID-JMRI22%3E
> 3.0.CO;2-G)
>
> Journal of Magnetic Resonance Imaging 11;223-227 (2000).
>
> To summarise (and assuming that not everyone can dowload this or be
> bothered to read it!) I have a projector (with it's main lens removed)
> with a plano-convex lens placed in front of it at a distance D1, a
> mirror a distance from the lens D2 and the mirror a distance D3 from the
> mirror (the mirror is required to angle the projection into the scanner).
>
> I want to keep the projected image to a specified size. How do I work
> out what focal length of lens is required and how far to place it from
> the projector knowing the distance from the projector to the screen
> (Dtotal)? I know that the projector has an LCD size of 1" (which I
> believe is the diagonal dimension?) which I assume is required for the
> calculation. I was also wondering, is the projector likely to have any
> internal lenses etc that might affect this calculation ,i.e. is one 1"
> LCD projector with lens removed the same as another, optically?
>
> Thanks for any help!
>
> Best regards
>
> Dave Brennan
>
If someone will do it for you who knows what to do, buy it. The chances are
that that will be cheaper than doing it yourself.
Bill
.
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