Re: Diode Laser, Quarter Wave Plate and a Linear Polariser

On Jul 29, 10:44 am, AES <sieg...@xxxxxxxxxxxx> wrote:
In article <1185703405.130326.239...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,

alex <aesbr...@xxxxxxxxxxx> wrote:

You mean that the reflection off say a lens must change the
polarisation of incident light?
So that the lhs circularly polarised light created by the QW plate
becomes RHs circularly polarised on reflection?

Yes, that's what happens.

Indeed, can be a bit confusing -- but try thinking either:

1) Going out thru QWP, then back thru QWP, equals going thru HWP,
equals 90 deg rotation of initial linearly polarized input; bouncing off
mirror along the way is incidental/irrelevant.

I'm confused. Bouncing right-hand polarized light from a mirror
results in left-hand-polarized light, doesn't it? Same E-field
but opposite travel direction means it has opposite helicity.
Is the mirror irrelevant because the light at that point is linearly
polarized?

.

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