Re: PSF function.. and convolution help needed

On Apr 16, 9:46 pm, "odprt...@xxxxxxxxx" <odprt...@xxxxxxxxx> wrote:
On Apr 16, 9:39 pm, "odprt...@xxxxxxxxx" <odprt...@xxxxxxxxx> wrote:



    F( X Y ) = F( X * Y )  and F( X * Y ) = F( X Y )  where * indicates the
convolution.

So, the amplitude of the light at the image plane is the Fourier transform
of the light at the pupil plane:

    Image(x,y) = F( L1(x,y) ) = F( L0(x,y) A(x,y) ) = F( L0(x,y) ) * F(
A(x,y) )

 something is not right in this equations, I think there is a mistake,
tell me if I am wrong here...
it should be :

  F( X)F( Y ) = F( X * Y )

what do u say?

also after reading few things, and reading this comment again.

in the end the PSF is nothing but a simple transform Fourier over the
aperture , and the light that hit it, no ?

also tell me if i understand what u say correctly
if you have the PSF of a system, then you can calculate how any signal
will look, by convulting this signal with the transform the PSF .
is that right? :)

thanks

meant:
if you have the PSF of a system, then you can calculate how any signal
 will look, by convulting this signal with  the PSF .
A
.

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