Re: Quarks
From: FrediFizzx (fredifizzx_at_hotmail.com)
Date: 12/28/04
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Date: Mon, 27 Dec 2004 17:10:53 -0800
"Old Man" <nomail@nomail.net> wrote in message
news:Gq6dnbeKLbIMUFLcRVn-2g@prairiewave.com...
|
| "FrediFizzx" <fredifizzx@hotmail.com> wrote in message
| news:338kc8F3tils3U1@individual.net...
| > "Old Man" <nomail@nomail.net> wrote in message
| > news:YvidnWhEntxLBVPcRVn-jA@prairiewave.com...
| > |
| > | "FrediFizzx" <fredifizzx@hotmail.com> wrote in message
| > | news:3378o2F3s32csU1@individual.net...
| > | > <bill_jones92057@yahoo.com> wrote in message
| > | > news:1104043351.635483.324970@f14g2000cwb.googlegroups.com...
| > | > | My knowledge of nuclear physics is less than minimal. So I think
| > that
| > | > | a proton has two 'up' quarks and one 'down' quark; and a neutron
has
| > | > | two 'down' quarks and one 'up' quark.
| > | > |
| > | > | A neutron decays into a proton plus an electron and some energy.
| > | >
| > | > A *free* neutron decays to a proton, electron and anti-electron
| > neutrino.
| > | >
| > | > | Essentially, it seems that one of the neutron's 'down' quarks
become
| > a
| > | > | 'up' quark in the proton?
| > | >
| > | > Yes. A neutron has slightly more rest mass energy than a proton so
it
| > is
| > | > favorable for it to decay to a lower rest mass energy. I have been
| > | > wondering though if the electron comes from pair production? With
the
| > | > positron decaying to a W+ and the anti-electron neutrino. The W+
then
| > | > converts the down quark to an up quark. Kind of hard to put this
into
| > a
| > | > proper Feynman diagram though since the "excess" energy of the
neutron
| > | > catalyzes the pair production.
| > | >
| > | > FrediFizzx
| > |
| > | Fizzx spews nonsense:
| > |
| > | n => p + W-
| > |
| > | d => u + W-
| > |
| > | W- => e- + [anti-neutrino]
| >
| > Yes, that is the "standard" way but this should also be an allowed
| > process;
| >
| > n + e+ => p + nubar_e
| >
| > If the positron comes from pair production then,
| >
| > n + e+ + e- => p + nubar_e + e-
| >
| > e+ => W+ + nubar_e
| >
| > W+ + d => u
| >
| > The neutron certainly has enough "excess" energy to cause pair
production
| > near it. Old man did not state any reason why the "standard" process is
| > preferred over this one. Nor have I been able to find any other reason
so
| > far. Perhaps Franz knows?
| >
| > FrediFizzx
|
| [# of vertices] ~ [order of magnitude]
Hmm... Still wondering if that really holds up in the case of free neutron
decay. Well, I will keep searching to see if anyone ever calculated the
lifetime via this pair production process. I think this process should be
considered for free neutron lifetime.
FrediFizzx
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