Re: cheating (Re: Understanding the HUP)

Ranando King wrote:
> No offense Autymn, but little is to be gained from your constant attempts at
> being an English teacher in this newsgroup. All but too often I've seen you

no point in your message

> post little more than a grammar correction and an insult. My understanding
> of the English language as used in the US is comprehensive enough to ensure
> that I get my point across whether or not my statements include typos. So
> please, refrain from playing editor and stick to the discussion of physics.

I refrain from nothing.

> The simple answer to your question is no. The first thing that you have to
> consider is that a photon is not an actual particle per se, but rather the
> simple physics notation for a single cycle of energy released as an EM wave.
> When an actual particle, preferably one that participates in EM
> interactions, especially an electron, encounters a photon, it absorbs the
> photon.

I know about that, which takes you to the squeezed state concept in my
second link, that measures a particle more precisely than the simple
HUP expression allows at the expense of fase information.

> So, if multiple photons met a particle, the photons themselves having a net
> 0 momentum, indeed there would be no net momentum change in the encountered
> particle. HOWEVER, in order to do such a thing, the photons would have to be
> targeted and timed in such a way that they meet the particle simultaneously.
> Any time delay at all between the encounters and the particle will have
> incurred a change in momentum.

Read the rest of the thread about cancelling this side-effect.

> To do such a precise targeting in an experiment would require knowledge of
> where the particle is and where it is going to a high degree of accuracy,
> i.e. precise knowledge of position and momentum simultaneously. So, in order
> to "cheat the HUP", you would need knowledge that violates the HUP.

Foreknowledge or hindknowledge will do it.

-Aut

.

Relevant Pages

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