Re: Magnetic field and relative motion
From: Pmb (someone_at_somewhere.com)
Date: 06/21/04
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Date: Sun, 20 Jun 2004 22:46:45 -0400
"xxein" <xxein@bellsouth.net> wrote in message
news:cce403e3.0406171624.3e7de408@posting.google.com...
> "Pmb" <someone@somewhere.com> wrote in message
news:<qvmdnfQKXbtLekzdRVn-tw@comcast.com>...
> > "Pmb" <someone@somewhere.com> wrote in message
> > news:ir2dnYsAgfel9kzdRVn-tA@comcast.com...
> > >
> > > "V.K.Tamhane" <vktamhane12@rediffmail.com> wrote
> > >
> > > > 1. Observer on the disc will notice magnetic field rotating along
with
> > > > the circuit and so seen from this frame, there is no emf generated
in
> > > > the circuit of stationary frame.
> > >
> > > It is incorrect to think of magnetic fields as rotating as you
mentioned.
> > > Doing so can lead to serious errors. You're also incorrectly assuning
that
> > > no E-field in one frame means no E-field in all other frames. That is
also
> > > incorrect.
> > >
> > >
> > > > 1. When the magnet producing the field is rotated and if the field
is
> > > > fixed then there will not be an emf.
> > > > 2. If the field is rotating along with the magnet then too, emf will
> > > > be zero. Because equal and opposite emf will be produced in the
> > > > lengths MB and CD.
> > >
> > > If the magnetic is rotated there will be no EMF but there will be an
> > > electric field
> >
> > To be precise - an EMF is defined as the line integral of force per unit
> > charge in a wire integrated around a complete circuit.
> >
> > Pmb
>
> xxein: And OWLS is defined as whatever we measure with TWLS? Just 'a
> shot on the dark'.
I dunno. I've never given much thought to that particular question in
relativity. I will someday soon though.
Pmb
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