Re: A Ballistic photon theory

From: Androcles (androc1es_at_nospamblueyonder.co.uk)
Date: 06/24/04 

Date: Thu, 24 Jun 2004 11:36:43 GMT

"Ballisticus" <B@..> wrote in message
news:c31kd0h82s6f2j9kal97rk3dtlc3cn10c8@4ax.com...
| On Wed, 23 Jun 2004 12:03:46 GMT, "Androcles"
| <androc1es@nospamblueyonder.co.uk> wrote:
|
| >
| >"Ballisticus" <B@..> wrote in message
| >news:3pcid0tm95koqthtcco8dmtu190c1tl21v@4ax.com...
| >| On Wed, 23 Jun 2004 06:55:34 GMT, "Androcles"
| >| <androc1es@nospamblueyonder.co.uk> wrote:
| >|
| >| >
| >| >"Ballisticus" <B@..> wrote in message
| >| >news:mdehd0dv6j1bt161c3kglg2m5o04qk1fl1@4ax.com...
| >|
| >| >| >> | "Androcles" <androc1es@nospamblueyonder.co.uk> wrote in message
| >| >| >> news:bpRBc.2536$kh7.22568162@news-text.cableinet.net...
| >| >| >> | >
| >| >| >> |
| >| >| >> | [snip]
| >| >| >> |
| >| >| >> | > = 1/sqrt(1).
| >| >| >> | > = 1/1
| >| >| >> |
| >| >|
| >| >| sqrt(-4) is -2.
| >| >
| >| >Huh?
| >| >sqrt(-1 * 4) = i*2, pal.
| >| >
| >| >
| >| >| Proof:
| >| >|
| >| >| Negation is a convention used to delineate a domain of numbers.
| >| >|
| >| >| A negative number represents 'the positive number of objects REMOVED
| >FROM
| >| >a
| >| >| group'.
| >| >
| >| >You should tell that to my bank manager. I can assure you that I
didn't
| >| >remove ANY objects from my account, and I pay my bills by standing
order
| >or
| >| >with plastic. Therefore my account CANNOT be overdrawn. :-)
| >| >
| >| >
| >| >|
| >| >| If +4 oranges are taken from a bucket, those four are mathematically
| >| >| represented by a negative number (-4).
| >| >
| >| >See what I mean? If the bucket is empty it isn't physically possible
to
| >take
| >| >4 oranges (or anything else), but if my bank account is empty I can
still
| >| >overdraw.
| >| >
| >| >| If sqrt(4) oranges are removed (that is, +2 oranges) that group of
two
| >is
| >| >| represented by (-2).
| >| >
| >| >The ADDITION of -2 oranges to the bucket is in no way connected to the
| >| >function sqrt(). Perhaps it is unfortunate that the binary operator
'-',
| >as
| >| >used in 2-1 = 1 has the same symbol and name as the unary operator '-'
as
| >| >used in -1, dropping the addition operator as in 2 + (-1) = 1.
Although
| >not
| >| >displayed, addition is implied. Likewise, "x is negative" implies the
| >value
| >| >x represents has a preceeding unary minus, even though x does not.
| >| >Consider Pythagoras. The square on the hypotenuse is equal to the sum
of
| >the
| >| >squares on the other two sides. x^2 +y^2 = z^2. This remains true even
if
| >x
| >| >= -4, y = 3, z = -5.
| >| >Rewriting this as z = sqrt(x^2 + y^2) does NOT imply z is positive,
since
| >| >clearly -5 is negative by definition. Dinky the Deranged claims it
does.
| >| >"This way sqrt is ALWAYS positive."-Dinky the Deranged.
| >| >Androcles
| >| >
| >|
| >| No A, I assure you, negative numbers exist in a separate domain from
| >positive
| >| numbers but should be treated the same. They are positive in the
negative
| >| domain.
| >|
| >| Sqrt(-4) defines the sqrt of the number 4, lying in the negative domain
| >(or
| >| plane). There is no reason to believe it doesn't equal (-2) which is
just
| >+2 in
| >| the negative plane.
| >
| >-2i and 2i are the two square roots of -4, pal, just as
|
| No, that's just a convention we have learnt to use.

If you think 2*2 = 4 is a "convention", then ok, it's a convention.
That doesn't entitle you to say "no".
(2 * i ) * (2* i) = -4, by definition of and conventional understanding of
'(' , '2', '*', 'i' , '-' ,')' , '=' and '4'. Changing the symbols to greek,
chinese, arabic, elephantese or dinkyspeak, writing it from right to left or
bottom to top, thereby using a different convention, isn't going the change
the concept.

|
| >[i.sin(2pi/3) + cos(2pi/3)],
| >[i.sin(4pi/3) + cos(4pi/3)]
| >and 1 are the three cube roots of 1,
| >i,-1,-i and 1 are the four fourth roots of 1.
|
| That's only if you accept the initial relationship sqrt(-1) = i

We need to call them something. Would you prefer j instead?
j,-1,-j and 1 are the four fourth roots of 1.

The symbol '1' representing the quantity 'one', when multiplied by the
quantity '1' is equal to the quantity we call '1'.
The symbol 'i' representing the quantity 'sqrt(-1)', when multiplied by the
quantity 'i' is equal to the quantity we call '-1'.

|
| It just so happens that orthogonal planes can be mathematically
accommodated
| using complex notation but in essence, negative numbers are just positive
| numbers along the negative axis.
|
|
| >And if Dinky the Deranged hasn't caught on yet, there are exactly 'n' nth
| >roots to any complex number, including (1,i0).
|
| Dinky can't do much beyond fumbling.
Yes, well, that's been long established.

|
| >|
| >| Whatever happened to Spaceman anyway. He disappeared rather quickly
from
| >this
| >| NG.
| >|
| >| Incidentally, I have a problem with the ballistic theory. Thermal
| >velocities at
| >| 6000C are highly significant.
| >| Light from a star comes from many sources moving at vastly different
| >speeds.
| >| I don't know how to cope with this yet. only thought of it last night.
| >
| >Of course. We can only take the mean of the bell curve. That applies to
our
| >own sun as well. Remember that our sun has an "atmosphere", albeit hotter
| >and of different elements to our own.
|
| Trouble is, at large distances, the brightness curves are greatly
afffected by
| thermal velocities at the source.
| There might be more significance in this than we think.,

Figure out the mean and standard deviation then. Oh, and don't forget the
spin of the star.
Androcles

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