Re: Hafele & Keating, Einstein, Dingle,Cocke, and Scott Murray

From: Harry (harald.vanlintel_at_epfl.ch)
Date: 07/23/04 

Date: Fri, 23 Jul 2004 15:34:05 +0200

OK then - still one more remark. ;-)

You wrote that in the inertial frame, g=0 AND a little further, that a=g
whereby a = NOT 0....
In the inertial frame, all definitions are relative to that frame: g is NOT
relative to the earth but to the fictive inertial frame.
Thus NOT g=0 but g= GM/R^2 and in free fall, a= v^2/R and a=g.

Your weight is taken in the rotating frame of the earth. Just measure it in
an inertial frame - that's possible using a low-flying airplane...

Harald

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