Re: the heart of a paradox

From: V ertner Vergon (vergon_enterprises_at_highstream.net)
Date: 07/30/04 

Date: 30 Jul 2004 16:01:41 -0700

"Ken and Vicki" <kavs_delethis_@sysmatrix.net> wrote in message news:<WpGdna7bZYOU1pfcRVn-hQ@sysmatrix.net>...
> "Ken and Vicki" <kavs_delethis_@sysmatrix.net> wrote in message
> news:RridnXDJqdNw1ZfcRVn-ug@sysmatrix.net...
> >
> > ...I am also aware of some time dissynchronicity
> > (what relativists term "the relativity of simultaneity") entering into
> that
> > figuring. In fact, I can resolve the Twin Paradox with SR alone...
>
> View my treatment at http://sysmatrix.net/~kavs/kjs/addend4.html

Vergon:

I'm afraid you messed up.

Quote.

"STELLA-CUM-ALF'S RECKONING: No, it's Terra that travels

According to Stella's viewpoint, stock still in space, the "real
estate" consisting of Earth-to-buoy is a moving frame,"

Wrong.
If Stella is "stock still in space" then the distance Earth-Buoy is at
rest to her -- and it is to the moving Earth that the space is
contracted.

 and so is length-contracted to 0.67 light-year. And since it has a
velocity of .75C with respect to her, the distant buoy should arrive
when her clock reads 0.89 year. Upon its arrival, Stella figures that
Terra's clock back on Earth, being time-dilated from motion, must read
only 0.59 year. But the buoy clock reads 1.33 years. However, this is
as expected due to the clock dissynchronicity: the buoy clock has a
reading 0.75 year later than Earth's.
********
The *principle of relativity* had been around quite a while when
Einstein wrote his paper. This principle stated that if there was
motion between systems (translatory, rectilinear) neither system was
preferred and the relation of each to the other was the same. Neither
acceleration or the condition of being at rest was ascribed to any of
it.

Einstein added two conditions. (1) He described the results of the
elctrodynamics of the moving bodies -- and (2) he also described
conditions if one of the systems was considered stationary
(inertial)(his gedanken clock experiment).

You attempted solve the Twins paradox by use of the PRINCIPLE OF
RELATIVITY. Can't do as it violates the essence.

However, there is a solution -- a definate solution.

TIME CONTRACTION AND

THE TWIN PARADOX LAID TO REST

Not only will we lay the paradox to rest, but you will learn something
new
about the special theory of relativity. At least the opportunity is
there to learn.

We have the Twin situation with clocks A and B. B is inertial, A is
the traveling clock.

Both clocks are identical and keep identical time (like cesium
clocks).

Yet when the traveler's clock returns it shows less time than the
inertial clock.

Notwithstanding -- at no time did it ever beat slower -- nor did time
ever
slow down. (see footnote below).

THE PRESENTLY ACCEPTED EXPLANATION

The reason there is a transit time differential is because the
*original* distance the traveler set out to transit contracts (same as
the longitudinal rod in that system contracts) -- and since that
distance is shorter, the time to transit it is shorter.

Everyone seems to overlook the common knowledge that a rod imbedded in
a moving system contracts -- *but so does the entire system* for it is
the sum of all the rods in it.

Once A accelerates, the distance it is to travel is a moving
coordinate system relative to it. That distance is now contracted, the
time to transit it is less than originally supposed. That is why it is
the accelerated system that experiences the shorter (or less) time.

So we see there is no time slowing down, no time dilation, just a
*transit time differential*.

~~~~~~~~~~~~~

Now we enter a phase of adding to the picture of special relativity.

We see that clocks never vary, and conclude that transit time
differential is due to space contraction. But then the question
arises," Does it really contract?" How can just the fact that a clock
travels rapidly through a space cause it to contract?

Answer, it doesn't. The space -- despite what I said before -- does
*not* contract (only the observation of it does so).

I merely said that because that is the popular notion. Now I will
explain what
actually happens to make the transit time of A less.

v can be any velocity to infinity. In other words the moving observer
can attain any Newtonian velocity, but the fact is that light emitted
from
him will be received at c. Thus no matter what radial velocity he
attains,
his velocity will always be measured as less than c by the observer.

Thus, when A makes the journey to T (Turn around location), he is
traversing the distance at a much more rapid rate than B measures.

So the reason he makes the journey in less time than observed by B
is not that A-T has contracted, but that the velocity of A is greater
than
measured.

Sometimes a proposition stated in another way is clearer, so let me
restate it.

There is a theory called the Dual Velocity Theory of Relativity which
shows that, similar to the observation of longitudinal length
contracting, so does the *observation* of velocity.

Thus there are two velocities, the Newtonian velocity attained, and
the corresponding
relative velocity observed -- same as a rod, the Newtonian length in
the
moving system, and the relative length observed.

As the Newtonian velocity tends to infinity, the observed velocity
tends to
c.

That's why it requires infinite energy to attain the infinite velocity
that
appears as c -- and that's why the momentum goes to infinity as the
Newtonian velocity goes to infinity but is observed as c.

In fact, one will find that with all corresponding pairs of
Newtonian/relativistic velocities, the Newtonian parameters of kinetic
energy and momentum are found in the company of the corresponding
relativistic velocity.

THE Lorentz transformation is the ratio between the Newtonian and its
corresponding relativistic velocity. Where v is relative velocity and
V Newtonian. v/ sqrt(1 – v^2/c^2) = V, or
V * sqrt(1 – v^2/c^2) = v.

And v/V = sqrt(1 –v^2/c^2)

_____________________________

Time dilation given as t' = t (sqrt(1 –v^2/c^2) is erroneous and does
not exist. Empirically.
This is established every night when astronomers observe moving
clocks, viz., the emitting
elements of stars and galaxies. Any constant known emitter is a clock,
and the variation observed is of Doppler. Thus we have Doppler time
not time dilation.

In recounting the Twin paradox one must use Doppler time which shows
time to run faster as an object approaches. In doing so one will find
that the final result – the transit time differential – is
T ‘ = T sqrt(1 – v^2/c^2)

Application of the *principle* of relativity does not apply as one
coordinate system is designated as preferred.

Therefore, Einstein's theory should be modified to reflect that
observed time rate
is vector modified. His so called "time dilation" is in actuality the
Transit Time Differential.
_____________________________________
*
It is the observation of time that shows it to slow. In all coordinate
systems time is proper and
Immutable.

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