Re: Einstein's Doppler equation wrong?

From: Androcles (dummy_at_dummy.net)
Date: 11/11/04 

Date: Thu, 11 Nov 2004 17:10:05 GMT

"V ertner Vergon" <vergon_enterprises@highstream.net> wrote in message
news:b337f5db.0411110807.f7c4fd5@posting.google.com...
: "Androcles" <dummy@dummy.net> wrote in message
news:<aHGkd.13519$Q7.5265@fe1.news.blueyonder.co.uk>...
: > "V ertner Vergon" <vergon_enterprises@highstream.net> wrote in
message
: > news:b337f5db.0411110108.199829be@posting.google.com...
: > : H@..(Henri Wilson) wrote in message
: > news:<kqo3p0hplpmdr3mbjr1m2spefm5gmtgu5k@4ax.com>...
: > : Vergon:
: > :
: > : That's right oh wise one. You know it is *** even tho you
: > ADMITTEDLY
: > : know nothing about it --nor do you want to learn. Fair enough,
: > remain
: > : an ignoramous
: > : but don't expect anyone of intelligence to take you seriously.
: >
: > Nobody of intelligence will take you seriously either, when
: > you write
: > "THIS EXCHANGE IS TERMINATED
: > THIS EXCHANGE IS TERMINATED
: > THIS EXCHANGE IS TERMINATED
: > THIS EXCHANGE IS TERMINATED
: > THIS EXCHANGE IS TERMINATED",
: > you arsehole.
: > Androcles.
:
: Vergon:
:
: LOL
:
: A person of intelligence would NOT include you.
:
: That's why the exchange was terminated.

ROFL.
Hey folks, this is what the exchange terminated on:
"It is at once apparent that this result still holds good if the clock
moves from A to B in any polygonal line, and also when the points A
and B coincide. If we assume that the result proved for a polygonal
line is also valid for a continuously curved line, we arrive at this
result: "

Nor did he give a proof for a polygon. We can reduce his polygon from
5 to 4 to 3 to 2 sides, and then the motion is going the opposite
way on the X-axis. That has the "peculiar conseqence" of
xi = (x PLUS vt) / sqrt(1-v^2/c^2)

Einstein suckered Vergon with an assumption, but Vergon has no
intelligence

to see it, so he ran away instead.

Androcles

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